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200414012402113 = 567775335298121
BaseRepresentation
bin101101100100011010000110…
…000001000110100111000001
3222021121101121010000012122021
4231210122012001012213001
5202232040344133331423
61550124532024041441
760133302025550026
oct5544320601064701
9867541533005567
10200414012402113
1158949118244864
121a5896b3303281
1387a9c6395c103
14376c138bab54d
151828365c1a95d
hexb646860469c1

200414012402113 has 4 divisors (see below), whose sum is σ = 200414053377988. Its totient is φ = 200413971426240.

The previous prime is 200414012402057. The next prime is 200414012402129. The reversal of 200414012402113 is 311204210414002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 121126599097009 + 79287413305104 = 11005753^2 + 8904348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200414012402113 is a prime.

It is a super-2 number, since 2×2004140124021132 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200414012402213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11971308 + ... + 23326813.

It is an arithmetic number, because the mean of its divisors is an integer number (50103513344497).

Almost surely, 2200414012402113 is an apocalyptic number.

It is an amenable number.

200414012402113 is a deficient number, since it is larger than the sum of its proper divisors (40975875).

200414012402113 is an equidigital number, since it uses as much as digits as its factorization.

200414012402113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40975874.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 200414012402113 its reverse (311204210414002), we get a palindrome (511618222816115).

The spelling of 200414012402113 in words is "two hundred trillion, four hundred fourteen billion, twelve million, four hundred two thousand, one hundred thirteen".

Divisors: 1 5677753 35298121 200414012402113