Base | Representation |
---|---|
bin | 101101100100100011100001… |
… | …101111011111000110100011 |
3 | 222021122100202000011120211221 |
4 | 231210203201233133012203 |
5 | 202232222120123103212 |
6 | 1550133325051515511 |
7 | 60134111026240042 |
oct | 5544434157370643 |
9 | 867570660146757 |
10 | 200424141222307 |
11 | 58952445745342 |
12 | 1a58b65b458b97 |
13 | 87aabb9241042 |
14 | 376c81a0a4559 |
15 | 182875a072807 |
hex | b648e1bdf1a3 |
200424141222307 has 2 divisors, whose sum is σ = 200424141222308. Its totient is φ = 200424141222306.
The previous prime is 200424141222251. The next prime is 200424141222317. The reversal of 200424141222307 is 703222141424002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200424141222307 - 215 = 200424141189539 is a prime.
It is a super-3 number, since 3×2004241412223073 (a number of 44 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (200424141222317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100212070611153 + 100212070611154.
It is an arithmetic number, because the mean of its divisors is an integer number (100212070611154).
Almost surely, 2200424141222307 is an apocalyptic number.
200424141222307 is a deficient number, since it is larger than the sum of its proper divisors (1).
200424141222307 is an equidigital number, since it uses as much as digits as its factorization.
200424141222307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 34.
Adding to 200424141222307 its reverse (703222141424002), we get a palindrome (903646282646309).
The spelling of 200424141222307 in words is "two hundred trillion, four hundred twenty-four billion, one hundred forty-one million, two hundred twenty-two thousand, three hundred seven".
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