Base | Representation |
---|---|
bin | 1011101010101011000… |
… | …0011100010100011001 |
3 | 201011100112122200111021 |
4 | 2322222300130110121 |
5 | 11240441412234431 |
6 | 232024445402441 |
7 | 20323632056146 |
oct | 2725260342431 |
9 | 634315580437 |
10 | 200433321241 |
11 | 7800442592a |
12 | 32a18869421 |
13 | 15b9302938a |
14 | 99b587b3cd |
15 | 533151ab11 |
hex | 2eaac1c519 |
200433321241 has 2 divisors, whose sum is σ = 200433321242. Its totient is φ = 200433321240.
The previous prime is 200433321091. The next prime is 200433321251. The reversal of 200433321241 is 142123334002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122567209216 + 77866112025 = 350096^2 + 279045^2 .
It is a cyclic number.
It is not a de Polignac number, because 200433321241 - 223 = 200424932633 is a prime.
It is a super-3 number, since 3×2004333212413 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (200433321251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100216660620 + 100216660621.
It is an arithmetic number, because the mean of its divisors is an integer number (100216660621).
Almost surely, 2200433321241 is an apocalyptic number.
It is an amenable number.
200433321241 is a deficient number, since it is larger than the sum of its proper divisors (1).
200433321241 is an equidigital number, since it uses as much as digits as its factorization.
200433321241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 200433321241 its reverse (142123334002), we get a palindrome (342556655243).
The spelling of 200433321241 in words is "two hundred billion, four hundred thirty-three million, three hundred twenty-one thousand, two hundred forty-one".
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