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20043413211131 is a prime number
BaseRepresentation
bin1001000111010101110001…
…00001100100011111111011
32121222010112221002010121022
410203222320201210133323
510111342402240224011
6110343452241533055
74136042315152352
oct443527041443773
977863487063538
1020043413211131
116428400255122
1222b866a64418b
13b2511653644b
144d416bc74999
1524b5963348db
hex123ab88647fb

20043413211131 has 2 divisors, whose sum is σ = 20043413211132. Its totient is φ = 20043413211130.

The previous prime is 20043413211113. The next prime is 20043413211179. The reversal of 20043413211131 is 13111231434002.

Together with previous prime (20043413211113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20043413211131 - 226 = 20043346102267 is a prime.

It is a super-2 number, since 2×200434132111312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20043413211131.

It is not a weakly prime, because it can be changed into another prime (20043413211191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10021706605565 + 10021706605566.

It is an arithmetic number, because the mean of its divisors is an integer number (10021706605566).

Almost surely, 220043413211131 is an apocalyptic number.

20043413211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

20043413211131 is an equidigital number, since it uses as much as digits as its factorization.

20043413211131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 20043413211131 its reverse (13111231434002), we get a palindrome (33154644645133).

The spelling of 20043413211131 in words is "twenty trillion, forty-three billion, four hundred thirteen million, two hundred eleven thousand, one hundred thirty-one".