Base | Representation |
---|---|
bin | 101101100100101100110101… |
… | …001111101111101100100011 |
3 | 222021200022112021210220020211 |
4 | 231210230311033233230203 |
5 | 202232403100310404103 |
6 | 1550142100311314551 |
7 | 60134613433421464 |
oct | 5544546517575443 |
9 | 867608467726224 |
10 | 200434132122403 |
11 | 58956702304473 |
12 | 1a59158937ba57 |
13 | 87abb1c09354a |
14 | 376d0c6d38d6b |
15 | 1828b4223436d |
hex | b64b353efb23 |
200434132122403 has 4 divisors (see below), whose sum is σ = 201272768658720. Its totient is φ = 199595495586088.
The previous prime is 200434132122331. The next prime is 200434132122437. The reversal of 200434132122403 is 304221231434002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200434132122403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200434132122463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419318267800 + ... + 419318268277.
It is an arithmetic number, because the mean of its divisors is an integer number (50318192164680).
Almost surely, 2200434132122403 is an apocalyptic number.
200434132122403 is a deficient number, since it is larger than the sum of its proper divisors (838636536317).
200434132122403 is an equidigital number, since it uses as much as digits as its factorization.
200434132122403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 838636536316.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 200434132122403 its reverse (304221231434002), we get a palindrome (504655363556405).
The spelling of 200434132122403 in words is "two hundred trillion, four hundred thirty-four billion, one hundred thirty-two million, one hundred twenty-two thousand, four hundred three".
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