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2004443113 = 3595583407
BaseRepresentation
bin111011101111001…
…0101111111101001
312011200201021000211
41313132111333221
513101114134423
6530522101121
7100446325321
oct16736257751
95150637024
102004443113
11939501862
1247b34a7a1
1325c37181a
141502d4281
15bae8e10d
hex77795fe9

2004443113 has 4 divisors (see below), whose sum is σ = 2010026880. Its totient is φ = 1998859348.

The previous prime is 2004443107. The next prime is 2004443117. The reversal of 2004443113 is 3113444002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2004443113 - 25 = 2004443081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2004443117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2791345 + ... + 2792062.

It is an arithmetic number, because the mean of its divisors is an integer number (502506720).

Almost surely, 22004443113 is an apocalyptic number.

It is an amenable number.

2004443113 is a deficient number, since it is larger than the sum of its proper divisors (5583767).

2004443113 is an equidigital number, since it uses as much as digits as its factorization.

2004443113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5583766.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 2004443113 is about 44771.0075048574. The cubic root of 2004443113 is about 1260.8533551117.

Adding to 2004443113 its reverse (3113444002), we get a palindrome (5117887115).

The spelling of 2004443113 in words is "two billion, four million, four hundred forty-three thousand, one hundred thirteen".

Divisors: 1 359 5583407 2004443113