Base | Representation |
---|---|
bin | 11101001010110100010… |
… | …110010111001001110001 |
3 | 21002121220200201220001112 |
4 | 131022310112113021301 |
5 | 230320134003131232 |
6 | 4132502354043105 |
7 | 264550616205665 |
oct | 35126426271161 |
9 | 7077820656045 |
10 | 2004480520817 |
11 | 703105aa7455 |
12 | 284594579495 |
13 | 1170388aa818 |
14 | 6d0359688a5 |
15 | 3721b51e4b2 |
hex | 1d2b4597271 |
2004480520817 has 2 divisors, whose sum is σ = 2004480520818. Its totient is φ = 2004480520816.
The previous prime is 2004480520741. The next prime is 2004480520859. The reversal of 2004480520817 is 7180250844002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1569618088336 + 434862432481 = 1252844^2 + 659441^2 .
It is a cyclic number.
It is not a de Polignac number, because 2004480520817 - 212 = 2004480516721 is a prime.
It is not a weakly prime, because it can be changed into another prime (2004480523817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002240260408 + 1002240260409.
It is an arithmetic number, because the mean of its divisors is an integer number (1002240260409).
Almost surely, 22004480520817 is an apocalyptic number.
It is an amenable number.
2004480520817 is a deficient number, since it is larger than the sum of its proper divisors (1).
2004480520817 is an equidigital number, since it uses as much as digits as its factorization.
2004480520817 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 143360, while the sum is 41.
The spelling of 2004480520817 in words is "two trillion, four billion, four hundred eighty million, five hundred twenty thousand, eight hundred seventeen".
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