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2004534413043 = 3668178137681
BaseRepresentation
bin11101001010110111100…
…011111100011011110011
321002122001110010220021220
4131022313203330123303
5230320241302204133
64132512001120123
7264552142244121
oct35126743743363
97078043126256
102004534413043
11703133466488
122845aa629043
13117046ac9706
146d03cb96911
15372211175b3
hex1d2b78fc6f3

2004534413043 has 4 divisors (see below), whose sum is σ = 2672712550728. Its totient is φ = 1336356275360.

The previous prime is 2004534413029. The next prime is 2004534413069. The reversal of 2004534413043 is 3403144354002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2004534413043 - 214 = 2004534396659 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2004534412995 and 2004534413013.

It is not an unprimeable number, because it can be changed into a prime (2004534413023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334089068838 + ... + 334089068843.

It is an arithmetic number, because the mean of its divisors is an integer number (668178137682).

Almost surely, 22004534413043 is an apocalyptic number.

2004534413043 is a deficient number, since it is larger than the sum of its proper divisors (668178137685).

2004534413043 is an equidigital number, since it uses as much as digits as its factorization.

2004534413043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668178137684.

The product of its (nonzero) digits is 69120, while the sum is 33.

Adding to 2004534413043 its reverse (3403144354002), we get a palindrome (5407678767045).

The spelling of 2004534413043 in words is "two trillion, four billion, five hundred thirty-four million, four hundred thirteen thousand, forty-three".

Divisors: 1 3 668178137681 2004534413043