Base | Representation |
---|---|
bin | 10010101010110011… |
… | …010010100110000011 |
3 | 1220202000000221010222 |
4 | 102222303102212003 |
5 | 312023113111121 |
6 | 13113031213255 |
7 | 1306513304102 |
oct | 225263224603 |
9 | 56660027128 |
10 | 20045441411 |
11 | 8557146906 |
12 | 3a7521722b |
13 | 1b75c28148 |
14 | d82354039 |
15 | 7c4c450ab |
hex | 4aacd2983 |
20045441411 has 4 divisors (see below), whose sum is σ = 20071374192. Its totient is φ = 20019508632.
The previous prime is 20045441401. The next prime is 20045441453. The reversal of 20045441411 is 11414454002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20045441411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20045441401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12965231 + ... + 12966776.
It is an arithmetic number, because the mean of its divisors is an integer number (5017843548).
Almost surely, 220045441411 is an apocalyptic number.
20045441411 is a deficient number, since it is larger than the sum of its proper divisors (25932781).
20045441411 is an equidigital number, since it uses as much as digits as its factorization.
20045441411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25932780.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 20045441411 its reverse (11414454002), we get a palindrome (31459895413).
The spelling of 20045441411 in words is "twenty billion, forty-five million, four hundred forty-one thousand, four hundred eleven".
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