Base | Representation |
---|---|
bin | 11101001011101011110… |
… | …101100001000000111001 |
3 | 21002201022120102012122001 |
4 | 131023223311201000321 |
5 | 230324040311401203 |
6 | 4133135010501001 |
7 | 264612651640132 |
oct | 35135365410071 |
9 | 7081276365561 |
10 | 2005411434553 |
11 | 70354352374a |
12 | 2847b4294761 |
13 | 117156709057 |
14 | 6d0c3450c89 |
15 | 3727310591d |
hex | 1d2ebd61039 |
2005411434553 has 2 divisors, whose sum is σ = 2005411434554. Its totient is φ = 2005411434552.
The previous prime is 2005411434529. The next prime is 2005411434571. The reversal of 2005411434553 is 3554341145002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1146681172224 + 858730262329 = 1070832^2 + 926677^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2005411434553 is a prime.
It is not a weakly prime, because it can be changed into another prime (2005411734553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002705717276 + 1002705717277.
It is an arithmetic number, because the mean of its divisors is an integer number (1002705717277).
Almost surely, 22005411434553 is an apocalyptic number.
It is an amenable number.
2005411434553 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005411434553 is an equidigital number, since it uses as much as digits as its factorization.
2005411434553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 2005411434553 its reverse (3554341145002), we get a palindrome (5559752579555).
The spelling of 2005411434553 in words is "two trillion, five billion, four hundred eleven million, four hundred thirty-four thousand, five hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •