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200542135153 is a prime number
BaseRepresentation
bin1011101011000100111…
…1100010001101110001
3201011122010102000010011
42322301033202031301
511241202241311103
6232043333534521
720326423010653
oct2726117421561
9634563360104
10200542135153
117805a897388
1232a491a4441
1315bac7378c9
1499c60c46d3
15533ad61d6d
hex2eb13e2371

200542135153 has 2 divisors, whose sum is σ = 200542135154. Its totient is φ = 200542135152.

The previous prime is 200542135121. The next prime is 200542135169. The reversal of 200542135153 is 351531245002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 180494973409 + 20047161744 = 424847^2 + 141588^2 .

It is a cyclic number.

It is not a de Polignac number, because 200542135153 - 25 = 200542135121 is a prime.

It is not a weakly prime, because it can be changed into another prime (200542135753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100271067576 + 100271067577.

It is an arithmetic number, because the mean of its divisors is an integer number (100271067577).

Almost surely, 2200542135153 is an apocalyptic number.

It is an amenable number.

200542135153 is a deficient number, since it is larger than the sum of its proper divisors (1).

200542135153 is an equidigital number, since it uses as much as digits as its factorization.

200542135153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 200542135153 in words is "two hundred billion, five hundred forty-two million, one hundred thirty-five thousand, one hundred fifty-three".