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2005434144353 is a prime number
BaseRepresentation
bin11101001011101101001…
…100001001011001100001
321002201101011010222121202
4131023231030021121201
5230324112120104403
64133141141330545
7264613345653353
oct35135514113141
97081334128552
102005434144353
11703555324982
122847bba06a55
1311715b32a9c3
146d0c64830d3
15372750de688
hex1d2ed309661

2005434144353 has 2 divisors, whose sum is σ = 2005434144354. Its totient is φ = 2005434144352.

The previous prime is 2005434144299. The next prime is 2005434144361. The reversal of 2005434144353 is 3534414345002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007718837904 + 997715306449 = 1003852^2 + 998857^2 .

It is a cyclic number.

It is not a de Polignac number, because 2005434144353 - 26 = 2005434144289 is a prime.

It is a super-2 number, since 2×20054341443532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2005434144853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002717072176 + 1002717072177.

It is an arithmetic number, because the mean of its divisors is an integer number (1002717072177).

Almost surely, 22005434144353 is an apocalyptic number.

It is an amenable number.

2005434144353 is a deficient number, since it is larger than the sum of its proper divisors (1).

2005434144353 is an equidigital number, since it uses as much as digits as its factorization.

2005434144353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 2005434144353 its reverse (3534414345002), we get a palindrome (5539848489355).

The spelling of 2005434144353 in words is "two trillion, five billion, four hundred thirty-four million, one hundred forty-four thousand, three hundred fifty-three".