Base | Representation |
---|---|
bin | 11101001011110001001… |
… | …100010101001011101011 |
3 | 21002201112211111220212212 |
4 | 131023301030111023223 |
5 | 230324231313121413 |
6 | 4133151540555335 |
7 | 264615122536631 |
oct | 35136114251353 |
9 | 7081484456785 |
10 | 2005501301483 |
11 | 70358a224039 |
12 | 28481a3b2b4b |
13 | 11716c212554 |
14 | 6d0d1365351 |
15 | 3727ae57ca8 |
hex | 1d2f13152eb |
2005501301483 has 2 divisors, whose sum is σ = 2005501301484. Its totient is φ = 2005501301482.
The previous prime is 2005501301431. The next prime is 2005501301533. The reversal of 2005501301483 is 3841031055002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2005501301483 - 220 = 2005500252907 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (2005501301983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002750650741 + 1002750650742.
It is an arithmetic number, because the mean of its divisors is an integer number (1002750650742).
Almost surely, 22005501301483 is an apocalyptic number.
2005501301483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005501301483 is an equidigital number, since it uses as much as digits as its factorization.
2005501301483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 2005501301483 its reverse (3841031055002), we get a palindrome (5846532356485).
The spelling of 2005501301483 in words is "two trillion, five billion, five hundred one million, three hundred one thousand, four hundred eighty-three".
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