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20100085113 = 36700028371
BaseRepresentation
bin10010101110000011…
…101111010101111001
31220212210212010012210
4102232003233111321
5312131110210423
613122302325333
71311045622143
oct225603572571
956783763183
1020100085113
118584a79499
123a8b589849
131b8434b0b4
14d896d9c93
157c993ab93
hex4ae0ef579

20100085113 has 4 divisors (see below), whose sum is σ = 26800113488. Its totient is φ = 13400056740.

The previous prime is 20100085087. The next prime is 20100085121. The reversal of 20100085113 is 31158000102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20100085113 - 29 = 20100084601 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20100085113.

It is not an unprimeable number, because it can be changed into a prime (20100086113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3350014183 + ... + 3350014188.

It is an arithmetic number, because the mean of its divisors is an integer number (6700028372).

Almost surely, 220100085113 is an apocalyptic number.

It is an amenable number.

20100085113 is a deficient number, since it is larger than the sum of its proper divisors (6700028375).

20100085113 is an equidigital number, since it uses as much as digits as its factorization.

20100085113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6700028374.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 20100085113 its reverse (31158000102), we get a palindrome (51258085215).

The spelling of 20100085113 in words is "twenty billion, one hundred million, eighty-five thousand, one hundred thirteen".

Divisors: 1 3 6700028371 20100085113