201013100131113 has 24 divisors (see below), whose sum is σ = 290391969952968. Its totient is φ = 133990405016832.

The previous prime is 201013100131099. The next prime is 201013100131141. The reversal of 201013100131113 is 311131001310102.

201013100131113 is a `hidden beast` number, since 20 + 10 + 1 + 310 + 0 + 1 + 311 + 13 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 69229771716249 + 131783328414864 = 8320443^2 + 11479692^2 .

It is a de Polignac number, because none of the positive numbers 2^k-201013100131113 is a prime.

It is a super-2 number, since 2×201013100131113² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (201013100131163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3842481445 + ... + 3842533757.

It is an arithmetic number, because the mean of its divisors is an integer number (12099665414707).

Almost surely, 2^{201013100131113} is an apocalyptic number.

It is an amenable number.

201013100131113 is a deficient number, since it is larger than the sum of its proper divisors (89378869821855).

201013100131113 is a wasteful number, since it uses less digits than its factorization.

201013100131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102553 (or 102550 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 201013100131113 its reverse (311131001310102), we get a palindrome (512144101441215).

The spelling of 201013100131113 in words is "two hundred one trillion, thirteen billion, one hundred million, one hundred thirty-one thousand, one hundred thirteen".