Base | Representation |
---|---|
bin | 1011101101001010000… |
… | …0000101000001010011 |
3 | 201020002000100120122001 |
4 | 2323102200011001103 |
5 | 11243323112321042 |
6 | 232214545254431 |
7 | 20346306550243 |
oct | 2732240050123 |
9 | 636060316561 |
10 | 201100120147 |
11 | 78316858803 |
12 | 32b84034417 |
13 | 15c6b212744 |
14 | 9a3a251b23 |
15 | 536ed30bb7 |
hex | 2ed2805053 |
201100120147 has 2 divisors, whose sum is σ = 201100120148. Its totient is φ = 201100120146.
The previous prime is 201100120121. The next prime is 201100120211. The reversal of 201100120147 is 741021001102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201100120147 is a prime.
It is not a weakly prime, because it can be changed into another prime (201100120547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550060073 + 100550060074.
It is an arithmetic number, because the mean of its divisors is an integer number (100550060074).
Almost surely, 2201100120147 is an apocalyptic number.
201100120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
201100120147 is an equidigital number, since it uses as much as digits as its factorization.
201100120147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 201100120147 its reverse (741021001102), we get a palindrome (942121121249).
The spelling of 201100120147 in words is "two hundred one billion, one hundred million, one hundred twenty thousand, one hundred forty-seven".
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