Base | Representation |
---|---|
bin | 1001001001010001110110… |
… | …11100001000011011000011 |
3 | 2122012111111212001110100121 |
4 | 10210220323130020123003 |
5 | 10113440322213011042 |
6 | 110434231103001111 |
7 | 4143621251356552 |
oct | 444507334103303 |
9 | 78174455043317 |
10 | 20110034110147 |
11 | 6453687a95653 |
12 | 2309561899197 |
13 | b2b4a2894657 |
14 | 4d748bb9dd99 |
15 | 24d194e6a367 |
hex | 124a3b7086c3 |
20110034110147 has 2 divisors, whose sum is σ = 20110034110148. Its totient is φ = 20110034110146.
The previous prime is 20110034110039. The next prime is 20110034110181. The reversal of 20110034110147 is 74101143001102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20110034110147 is a prime.
It is a super-2 number, since 2×201100341101472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20110034110447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055017055073 + 10055017055074.
It is an arithmetic number, because the mean of its divisors is an integer number (10055017055074).
Almost surely, 220110034110147 is an apocalyptic number.
20110034110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110034110147 is an equidigital number, since it uses as much as digits as its factorization.
20110034110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 20110034110147 its reverse (74101143001102), we get a palindrome (94211177111249).
The spelling of 20110034110147 in words is "twenty trillion, one hundred ten billion, thirty-four million, one hundred ten thousand, one hundred forty-seven".
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