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20110034110147 is a prime number
BaseRepresentation
bin1001001001010001110110…
…11100001000011011000011
32122012111111212001110100121
410210220323130020123003
510113440322213011042
6110434231103001111
74143621251356552
oct444507334103303
978174455043317
1020110034110147
116453687a95653
122309561899197
13b2b4a2894657
144d748bb9dd99
1524d194e6a367
hex124a3b7086c3

20110034110147 has 2 divisors, whose sum is σ = 20110034110148. Its totient is φ = 20110034110146.

The previous prime is 20110034110039. The next prime is 20110034110181. The reversal of 20110034110147 is 74101143001102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20110034110147 is a prime.

It is a super-2 number, since 2×201100341101472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20110034110447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055017055073 + 10055017055074.

It is an arithmetic number, because the mean of its divisors is an integer number (10055017055074).

Almost surely, 220110034110147 is an apocalyptic number.

20110034110147 is a deficient number, since it is larger than the sum of its proper divisors (1).

20110034110147 is an equidigital number, since it uses as much as digits as its factorization.

20110034110147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 20110034110147 its reverse (74101143001102), we get a palindrome (94211177111249).

The spelling of 20110034110147 in words is "twenty trillion, one hundred ten billion, thirty-four million, one hundred ten thousand, one hundred forty-seven".