Base | Representation |
---|---|
bin | 101101101110011001111001… |
… | …110010111001111101111011 |
3 | 222101001001211121100211222211 |
4 | 231232121321302321331323 |
5 | 202324314323020333313 |
6 | 1551412305221555551 |
7 | 60234032206036051 |
oct | 5556317162717573 |
9 | 871031747324884 |
10 | 201101002121083 |
11 | 59093502006789 |
12 | 1a67a87a875bb7 |
13 | 88299878678bc |
14 | 37934aa22c1d1 |
15 | 183b1729dee3d |
hex | b6e679cb9f7b |
201101002121083 has 2 divisors, whose sum is σ = 201101002121084. Its totient is φ = 201101002121082.
The previous prime is 201101002121059. The next prime is 201101002121087. The reversal of 201101002121083 is 380121200101102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201101002121083 is a prime.
It is a super-2 number, since 2×2011010021210832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201101002121087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550501060541 + 100550501060542.
It is an arithmetic number, because the mean of its divisors is an integer number (100550501060542).
Almost surely, 2201101002121083 is an apocalyptic number.
201101002121083 is a deficient number, since it is larger than the sum of its proper divisors (1).
201101002121083 is an equidigital number, since it uses as much as digits as its factorization.
201101002121083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 201101002121083 its reverse (380121200101102), we get a palindrome (581222202222185).
The spelling of 201101002121083 in words is "two hundred one trillion, one hundred one billion, two million, one hundred twenty-one thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •