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201101134001 = 491409574611
BaseRepresentation
bin1011101101001010001…
…1111100100010110001
3201020002002021002101012
42323102203330202301
511243323342242001
6232215023120305
720346321302135
oct2732243744261
9636062232335
10201101134001
11783173904a9
1232b84443095
1315c6b4a9061
149a3a4373c5
15536ee812bb
hex2ed28fc8b1

201101134001 has 4 divisors (see below), whose sum is σ = 201510709104. Its totient is φ = 200691558900.

The previous prime is 201101133997. The next prime is 201101134033. The reversal of 201101134001 is 100431101102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201101134001 - 22 = 201101133997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201101134061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204786815 + ... + 204787796.

It is an arithmetic number, because the mean of its divisors is an integer number (50377677276).

Almost surely, 2201101134001 is an apocalyptic number.

It is an amenable number.

201101134001 is a deficient number, since it is larger than the sum of its proper divisors (409575103).

201101134001 is an equidigital number, since it uses as much as digits as its factorization.

201101134001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 409575102.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 201101134001 its reverse (100431101102), we get a palindrome (301532235103).

The spelling of 201101134001 in words is "two hundred one billion, one hundred one million, one hundred thirty-four thousand, one".

Divisors: 1 491 409574611 201101134001