Base | Representation |
---|---|
bin | 11101010000111001110… |
… | …001111111100010100001 |
3 | 21010020210000211011100102 |
4 | 131100321301333202201 |
5 | 230422024102214103 |
6 | 4135502551232145 |
7 | 265201542551111 |
oct | 35207161774241 |
9 | 7106700734312 |
10 | 2011014101153 |
11 | 705959040022 |
12 | 2858b8678655 |
13 | 11783a3881a5 |
14 | 6d495591041 |
15 | 3749ee04e88 |
hex | 1d439c7f8a1 |
2011014101153 has 2 divisors, whose sum is σ = 2011014101154. Its totient is φ = 2011014101152.
The previous prime is 2011014101093. The next prime is 2011014101183. The reversal of 2011014101153 is 3511014101102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1997040969889 + 13973131264 = 1413167^2 + 118208^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011014101153 - 220 = 2011013052577 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011014101183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005507050576 + 1005507050577.
It is an arithmetic number, because the mean of its divisors is an integer number (1005507050577).
Almost surely, 22011014101153 is an apocalyptic number.
It is an amenable number.
2011014101153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011014101153 is an equidigital number, since it uses as much as digits as its factorization.
2011014101153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 2011014101153 its reverse (3511014101102), we get a palindrome (5522028202255).
The spelling of 2011014101153 in words is "two trillion, eleven billion, fourteen million, one hundred one thousand, one hundred fifty-three".
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