Base | Representation |
---|---|
bin | 101101101110011010110110… |
… | …100110010000000101111011 |
3 | 222101001011110200211221102101 |
4 | 231232122312212100011323 |
5 | 202324323420141322021 |
6 | 1551412554342044231 |
7 | 60234066403503652 |
oct | 5556326646200573 |
9 | 871034420757371 |
10 | 201102022214011 |
11 | 59093985903696 |
12 | 1a67ab04419677 |
13 | 8829abacbb599 |
14 | 37935658ca199 |
15 | 183b1d233ea91 |
hex | b6e6b699017b |
201102022214011 has 2 divisors, whose sum is σ = 201102022214012. Its totient is φ = 201102022214010.
The previous prime is 201102022213927. The next prime is 201102022214017. The reversal of 201102022214011 is 110412220201102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201102022214011 - 245 = 165917650125179 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201102022214011.
It is not a weakly prime, because it can be changed into another prime (201102022214017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100551011107005 + 100551011107006.
It is an arithmetic number, because the mean of its divisors is an integer number (100551011107006).
Almost surely, 2201102022214011 is an apocalyptic number.
201102022214011 is a deficient number, since it is larger than the sum of its proper divisors (1).
201102022214011 is an equidigital number, since it uses as much as digits as its factorization.
201102022214011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 201102022214011 its reverse (110412220201102), we get a palindrome (311514242415113).
The spelling of 201102022214011 in words is "two hundred one trillion, one hundred two billion, twenty-two million, two hundred fourteen thousand, eleven".
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