Base | Representation |
---|---|
bin | 101101101110011011000111… |
… | …110100011001000010010101 |
3 | 222101001012012211111120020000 |
4 | 231232123013310121002111 |
5 | 202324330013122231313 |
6 | 1551413043142401513 |
7 | 60234106512333231 |
oct | 5556330764310225 |
9 | 871035184446200 |
10 | 201102311133333 |
11 | 590940139a9a95 |
12 | 1a67ab85130299 |
13 | 8829b35b0996c |
14 | 37935920175c1 |
15 | 183b1ec8b0673 |
hex | b6e6c7d19095 |
201102311133333 has 10 divisors (see below), whose sum is σ = 300412094409174. Its totient is φ = 134068207422168.
The previous prime is 201102311133307. The next prime is 201102311133377. The reversal of 201102311133333 is 333331113201102.
201102311133333 is a `hidden beast` number, since 2 + 0 + 1 + 1 + 0 + 2 + 311 + 13 + 3 + 333 = 666.
It can be written as a sum of positive squares in only one way, i.e., 149390924063364 + 51711387069969 = 12222558^2 + 7191063^2 .
It is not a de Polignac number, because 201102311133333 - 213 = 201102311125141 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 201102311133297 and 201102311133306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201102311133133) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1241372290866 + ... + 1241372291027.
Almost surely, 2201102311133333 is an apocalyptic number.
It is an amenable number.
201102311133333 is a deficient number, since it is larger than the sum of its proper divisors (99309783275841).
201102311133333 is an equidigital number, since it uses as much as digits as its factorization.
201102311133333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2482744581905 (or 2482744581896 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 201102311133333 its reverse (333331113201102), we get a palindrome (534433424334435).
The spelling of 201102311133333 in words is "two hundred one trillion, one hundred two billion, three hundred eleven million, one hundred thirty-three thousand, three hundred thirty-three".
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