Base | Representation |
---|---|
bin | 1011101101001100010… |
… | …1110100010100100001 |
3 | 201020002200222012101001 |
4 | 2323103011310110201 |
5 | 11243333130410332 |
6 | 232215541312001 |
7 | 20346456623101 |
oct | 2732305642441 |
9 | 636080865331 |
10 | 201110013217 |
11 | 783213a55a3 |
12 | 32b87405601 |
13 | 15c70297729 |
14 | 9a3b6a9201 |
15 | 5370b370e7 |
hex | 2ed3174521 |
201110013217 has 2 divisors, whose sum is σ = 201110013218. Its totient is φ = 201110013216.
The previous prime is 201110013199. The next prime is 201110013239. The reversal of 201110013217 is 712310011102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 143344774881 + 57765238336 = 378609^2 + 240344^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201110013217 is a prime.
It is a super-2 number, since 2×2011100132172 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201110013194 and 201110013203.
It is not a weakly prime, because it can be changed into another prime (201110023217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555006608 + 100555006609.
It is an arithmetic number, because the mean of its divisors is an integer number (100555006609).
Almost surely, 2201110013217 is an apocalyptic number.
It is an amenable number.
201110013217 is a deficient number, since it is larger than the sum of its proper divisors (1).
201110013217 is an equidigital number, since it uses as much as digits as its factorization.
201110013217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 201110013217 its reverse (712310011102), we get a palindrome (913420024319).
The spelling of 201110013217 in words is "two hundred one billion, one hundred ten million, thirteen thousand, two hundred seventeen".
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