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201110076992483 is a prime number
BaseRepresentation
bin101101101110100010010110…
…101100110010101111100011
3222101001221021001100002020222
4231232202112230302233203
5202324441414202224413
61551420405515553255
760234503121133061
oct5556422654625743
9871057231302228
10201110076992483
11590973395959aa
121a680591a5b82b
13882a7a29a0aa9
143793acb573031
15183b50455ab08
hexb6e896b32be3

201110076992483 has 2 divisors, whose sum is σ = 201110076992484. Its totient is φ = 201110076992482.

The previous prime is 201110076992459. The next prime is 201110076992501. The reversal of 201110076992483 is 384299670011102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201110076992483 is a prime.

It is a super-3 number, since 3×2011100769924833 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (201110076992183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555038496241 + 100555038496242.

It is an arithmetic number, because the mean of its divisors is an integer number (100555038496242).

Almost surely, 2201110076992483 is an apocalyptic number.

201110076992483 is a deficient number, since it is larger than the sum of its proper divisors (1).

201110076992483 is an equidigital number, since it uses as much as digits as its factorization.

201110076992483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 201110076992483 in words is "two hundred one trillion, one hundred ten billion, seventy-six million, nine hundred ninety-two thousand, four hundred eighty-three".