Base | Representation |
---|---|
bin | 11101010000111111000… |
… | …001011000000111001011 |
3 | 21010021000011020220101121 |
4 | 131100333001120013023 |
5 | 230422214104120133 |
6 | 4135515411500111 |
7 | 265203661055314 |
oct | 35207701300713 |
9 | 7107004226347 |
10 | 2011102020043 |
11 | 7059a372a866 |
12 | 285921bb7637 |
13 | 11785265babc |
14 | 6d4a311960b |
15 | 374a79c002d |
hex | 1d43f0581cb |
2011102020043 has 2 divisors, whose sum is σ = 2011102020044. Its totient is φ = 2011102020042.
The previous prime is 2011102020019. The next prime is 2011102020077. The reversal of 2011102020043 is 3400202011102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011102020043 - 213 = 2011102011851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2011102019999 and 2011102020026.
It is not a weakly prime, because it can be changed into another prime (2011102020443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005551010021 + 1005551010022.
It is an arithmetic number, because the mean of its divisors is an integer number (1005551010022).
Almost surely, 22011102020043 is an apocalyptic number.
2011102020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011102020043 is an equidigital number, since it uses as much as digits as its factorization.
2011102020043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 2011102020043 its reverse (3400202011102), we get a palindrome (5411304031145).
The spelling of 2011102020043 in words is "two trillion, eleven billion, one hundred two million, twenty thousand, forty-three".
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