Base | Representation |
---|---|
bin | 10010101110101101… |
… | …110000100100100001 |
3 | 1220220120120202001201 |
4 | 102232231300210201 |
5 | 312141420201233 |
6 | 13123334401201 |
7 | 1311241350112 |
oct | 225655604441 |
9 | 56816522051 |
10 | 20111100193 |
11 | 8590212268 |
12 | 3a93200201 |
13 | 1b867069b2 |
14 | d8ad66209 |
15 | 7ca8b477d |
hex | 4aeb70921 |
20111100193 has 2 divisors, whose sum is σ = 20111100194. Its totient is φ = 20111100192.
The previous prime is 20111100173. The next prime is 20111100209. The reversal of 20111100193 is 39100111102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19289876544 + 821223649 = 138888^2 + 28657^2 .
It is a cyclic number.
It is not a de Polignac number, because 20111100193 - 221 = 20109003041 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20111100193.
It is not a weakly prime, because it can be changed into another prime (20111100133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055550096 + 10055550097.
It is an arithmetic number, because the mean of its divisors is an integer number (10055550097).
Almost surely, 220111100193 is an apocalyptic number.
It is an amenable number.
20111100193 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111100193 is an equidigital number, since it uses as much as digits as its factorization.
20111100193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 20111100193 its reverse (39100111102), we get a palindrome (59211211295).
The spelling of 20111100193 in words is "twenty billion, one hundred eleven million, one hundred thousand, one hundred ninety-three".
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