Base | Representation |
---|---|
bin | 11101010001000000001… |
… | …101100110000011111001 |
3 | 21010021001112211222220111 |
4 | 131101000031212003321 |
5 | 230422234213000441 |
6 | 4135521404024321 |
7 | 265204322642263 |
oct | 35210015460371 |
9 | 7107045758814 |
10 | 2011122000121 |
11 | 705a03a37123 |
12 | 2859288320a1 |
13 | 117856836130 |
14 | 6d4a5a3ab33 |
15 | 374a961a081 |
hex | 1d4403660f9 |
2011122000121 has 16 divisors (see below), whose sum is σ = 2169095318208. Its totient is φ = 1853618011200.
The previous prime is 2011122000101. The next prime is 2011122000179. The reversal of 2011122000121 is 1210002211102.
It is a cyclic number.
It is not a de Polignac number, because 2011122000121 - 25 = 2011122000089 is a prime.
It is a super-2 number, since 2×20111220001212 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is not an unprimeable number, because it can be changed into a prime (2011122000101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25590930 + ... + 25669396.
It is an arithmetic number, because the mean of its divisors is an integer number (135568457388).
Almost surely, 22011122000121 is an apocalyptic number.
It is an amenable number.
2011122000121 is a deficient number, since it is larger than the sum of its proper divisors (157973318087).
2011122000121 is a wasteful number, since it uses less digits than its factorization.
2011122000121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81432.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2011122000121 its reverse (1210002211102), we get a palindrome (3221124211223).
The spelling of 2011122000121 in words is "two trillion, eleven billion, one hundred twenty-two million, one hundred twenty-one", and thus it is an aban number.
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