Base | Representation |
---|---|
bin | 101101101110100100010110… |
… | …100011110001010110101011 |
3 | 222101002010210112202101212101 |
4 | 231232210112203301112223 |
5 | 202330010312330024042 |
6 | 1551421402425154231 |
7 | 60234610226264254 |
oct | 5556442643612653 |
9 | 871063715671771 |
10 | 201112222111147 |
11 | 5909823a440346 |
12 | 1a680a9032b977 |
13 | 882aa55228289 |
14 | 3793c52405b2b |
15 | 183b5cca366b7 |
hex | b6e9168f15ab |
201112222111147 has 2 divisors, whose sum is σ = 201112222111148. Its totient is φ = 201112222111146.
The previous prime is 201112222111067. The next prime is 201112222111247. The reversal of 201112222111147 is 741111222211102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201112222111147 - 27 = 201112222111019 is a prime.
It is a super-3 number, since 3×2011122221111473 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (201112222111247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556111055573 + 100556111055574.
It is an arithmetic number, because the mean of its divisors is an integer number (100556111055574).
Almost surely, 2201112222111147 is an apocalyptic number.
201112222111147 is a deficient number, since it is larger than the sum of its proper divisors (1).
201112222111147 is an equidigital number, since it uses as much as digits as its factorization.
201112222111147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 28.
Adding to 201112222111147 its reverse (741111222211102), we get a palindrome (942223444322249).
The spelling of 201112222111147 in words is "two hundred one trillion, one hundred twelve billion, two hundred twenty-two million, one hundred eleven thousand, one hundred forty-seven".
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