Base | Representation |
---|---|
bin | 1011101101001101000… |
… | …1110000011011011011 |
3 | 201020002220212012122001 |
4 | 2323103101300123123 |
5 | 11243334431034003 |
6 | 232220132341431 |
7 | 20346525336613 |
oct | 2732321603333 |
9 | 636086765561 |
10 | 201113143003 |
11 | 78323142aa3 |
12 | 32b88474877 |
13 | 15c70b22186 |
14 | 9a3bc81a43 |
15 | 537105461d |
hex | 2ed34706db |
201113143003 has 2 divisors, whose sum is σ = 201113143004. Its totient is φ = 201113143002.
The previous prime is 201113142961. The next prime is 201113143027. The reversal of 201113143003 is 300341311102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201113143003 is a prime.
It is not a weakly prime, because it can be changed into another prime (201113141003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556571501 + 100556571502.
It is an arithmetic number, because the mean of its divisors is an integer number (100556571502).
Almost surely, 2201113143003 is an apocalyptic number.
201113143003 is a deficient number, since it is larger than the sum of its proper divisors (1).
201113143003 is an equidigital number, since it uses as much as digits as its factorization.
201113143003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 201113143003 its reverse (300341311102), we get a palindrome (501454454105).
The spelling of 201113143003 in words is "two hundred one billion, one hundred thirteen million, one hundred forty-three thousand, three".
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