Base | Representation |
---|---|
bin | 11101010001000001011… |
… | …000001100000001001011 |
3 | 21010021002220122110010112 |
4 | 131101001120030001023 |
5 | 230422304214214001 |
6 | 4135523343104535 |
7 | 265204651103354 |
oct | 35210130140113 |
9 | 7107086573115 |
10 | 2011141554251 |
11 | 705a13a82465 |
12 | 2859332a214b |
13 | 11785a8c161b |
14 | 6d4a848ad2b |
15 | 374ab1cdcbb |
hex | 1d44160c04b |
2011141554251 has 2 divisors, whose sum is σ = 2011141554252. Its totient is φ = 2011141554250.
The previous prime is 2011141554211. The next prime is 2011141554259. The reversal of 2011141554251 is 1524551411102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011141554251 - 26 = 2011141554187 is a prime.
It is a super-3 number, since 3×20111415542513 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2011141554259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005570777125 + 1005570777126.
It is an arithmetic number, because the mean of its divisors is an integer number (1005570777126).
Almost surely, 22011141554251 is an apocalyptic number.
2011141554251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011141554251 is an equidigital number, since it uses as much as digits as its factorization.
2011141554251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8000, while the sum is 32.
Adding to 2011141554251 its reverse (1524551411102), we get a palindrome (3535692965353).
The spelling of 2011141554251 in words is "two trillion, eleven billion, one hundred forty-one million, five hundred fifty-four thousand, two hundred fifty-one".
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