Base | Representation |
---|---|
bin | 101101101110101011101101… |
… | …011000110011000001010001 |
3 | 222101002220012001110221011002 |
4 | 231232223231120303001101 |
5 | 202330123002023144441 |
6 | 1551425150324231345 |
7 | 60235310044305416 |
oct | 5556535530630121 |
9 | 871086161427132 |
10 | 201120121303121 |
11 | 590a0623315179 |
12 | 1a68251583b555 |
13 | 882b713903b77 |
14 | 37943a154c10d |
15 | 183b8e126cb9b |
hex | b6eaed633051 |
201120121303121 has 4 divisors (see below), whose sum is σ = 201137836466532. Its totient is φ = 201102406139712.
The previous prime is 201120121303103. The next prime is 201120121303139. The reversal of 201120121303121 is 121303121021102.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (201120121303103) and next prime (201120121303139).
It can be written as a sum of positive squares in 2 ways, for example, as 152211932256400 + 48908189046721 = 12337420^2 + 6993439^2 .
It is a cyclic number.
It is not a de Polignac number, because 201120121303121 - 230 = 201119047561297 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201120121303093 and 201120121303102.
It is not an unprimeable number, because it can be changed into a prime (201120121305121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8857564676 + ... + 8857587381.
It is an arithmetic number, because the mean of its divisors is an integer number (50284459116633).
Almost surely, 2201120121303121 is an apocalyptic number.
It is an amenable number.
201120121303121 is a deficient number, since it is larger than the sum of its proper divisors (17715163411).
201120121303121 is a wasteful number, since it uses less digits than its factorization.
201120121303121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17715163410.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 201120121303121 its reverse (121303121021102), we get a palindrome (322423242324223).
The spelling of 201120121303121 in words is "two hundred one trillion, one hundred twenty billion, one hundred twenty-one million, three hundred three thousand, one hundred twenty-one".
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