Base | Representation |
---|---|
bin | 10010101110110001… |
… | …100111100111110001 |
3 | 1220220122111011011020 |
4 | 102232301213213301 |
5 | 312142200041423 |
6 | 13123412210053 |
7 | 1311253063242 |
oct | 225661474761 |
9 | 56818434136 |
10 | 20112112113 |
11 | 8590843565 |
12 | 3a93609929 |
13 | 1b8699c472 |
14 | d8b14acc9 |
15 | 7caa144e3 |
hex | 4aec679f1 |
20112112113 has 8 divisors (see below), whose sum is σ = 27386706048. Its totient is φ = 13122796464.
The previous prime is 20112112087. The next prime is 20112112117. The reversal of 20112112113 is 31121121102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-20112112113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20112112092 and 20112112101.
It is not an unprimeable number, because it can be changed into a prime (20112112117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71319406 + ... + 71319687.
It is an arithmetic number, because the mean of its divisors is an integer number (3423338256).
Almost surely, 220112112113 is an apocalyptic number.
It is an amenable number.
20112112113 is a deficient number, since it is larger than the sum of its proper divisors (7274593935).
20112112113 is a wasteful number, since it uses less digits than its factorization.
20112112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142639143.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 20112112113 its reverse (31121121102), we get a palindrome (51233233215).
The spelling of 20112112113 in words is "twenty billion, one hundred twelve million, one hundred twelve thousand, one hundred thirteen".
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