2011224131401 has 2 divisors, whose sum is σ = 2011224131402. Its totient is φ = 2011224131400.

The previous prime is 2011224131377. The next prime is 2011224131471. The reversal of 2011224131401 is 1041314221102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1838467521801 + 172756609600 = 1355901^2 + 415640^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2011224131401 is a prime.

It is not a weakly prime, because it can be changed into another prime (2011224131471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005612065700 + 1005612065701.

It is an arithmetic number, because the mean of its divisors is an integer number (1005612065701).

Almost surely, 2^{2011224131401} is an apocalyptic number.

It is an amenable number.

2011224131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011224131401 is an equidigital number, since it uses as much as digits as its factorization.

2011224131401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 2011224131401 its reverse (1041314221102), we get a palindrome (3052538352503).

The spelling of 2011224131401 in words is "two trillion, eleven billion, two hundred twenty-four million, one hundred thirty-one thousand, four hundred one".