Base | Representation |
---|---|
bin | 11101010001001100001… |
… | …001010110001010010011 |
3 | 21010021120111120212100201 |
4 | 131101030021112022103 |
5 | 230423141441304021 |
6 | 4135553315200031 |
7 | 265212303504316 |
oct | 35211411261223 |
9 | 7107514525321 |
10 | 2011322213011 |
11 | 705aa6a55021 |
12 | 2859838a6017 |
13 | 1178891662b7 |
14 | 6d4c447697d |
15 | 374bbeb7591 |
hex | 1d44c256293 |
2011322213011 has 2 divisors, whose sum is σ = 2011322213012. Its totient is φ = 2011322213010.
The previous prime is 2011322212943. The next prime is 2011322213023. The reversal of 2011322213011 is 1103122231102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011322213011 - 217 = 2011322081939 is a prime.
It is a super-2 number, since 2×20113222130112 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2011322213011.
It is not a weakly prime, because it can be changed into another prime (2011322210011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005661106505 + 1005661106506.
It is an arithmetic number, because the mean of its divisors is an integer number (1005661106506).
Almost surely, 22011322213011 is an apocalyptic number.
2011322213011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011322213011 is an equidigital number, since it uses as much as digits as its factorization.
2011322213011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2011322213011 its reverse (1103122231102), we get a palindrome (3114444444113).
The spelling of 2011322213011 in words is "two trillion, eleven billion, three hundred twenty-two million, two hundred thirteen thousand, eleven".
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