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2011331030001 = 3670443676667
BaseRepresentation
bin11101010001001100101…
…010111110101111110001
321010021121010011210222220
4131101030222332233301
5230423201220430001
64135554232151253
7265212441445656
oct35211452765761
97107533153886
102011331030001
11706000a27397
12285986838529
1311788ac32557
146d4c56cdc2d
15374bcb59c36
hex1d44cabebf1

2011331030001 has 4 divisors (see below), whose sum is σ = 2681774706672. Its totient is φ = 1340887353332.

The previous prime is 2011331029987. The next prime is 2011331030021. The reversal of 2011331030001 is 1000301331102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2011331030001 - 29 = 2011331029489 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2011331030021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335221838331 + ... + 335221838336.

It is an arithmetic number, because the mean of its divisors is an integer number (670443676668).

Almost surely, 22011331030001 is an apocalyptic number.

It is an amenable number.

2011331030001 is a deficient number, since it is larger than the sum of its proper divisors (670443676671).

2011331030001 is an equidigital number, since it uses as much as digits as its factorization.

2011331030001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670443676670.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 2011331030001 its reverse (1000301331102), we get a palindrome (3011632361103).

The spelling of 2011331030001 in words is "two trillion, eleven billion, three hundred thirty-one million, thirty thousand, one".

Divisors: 1 3 670443676667 2011331030001