Base | Representation |
---|---|
bin | 10010101110110110… |
… | …010001010010000011 |
3 | 1220220201210002121110 |
4 | 102232312101102003 |
5 | 312143003100311 |
6 | 13123454254403 |
7 | 1311266331642 |
oct | 225666212203 |
9 | 56821702543 |
10 | 20113331331 |
11 | 85914a6585 |
12 | 3a93ab7403 |
13 | 1b870083b2 |
14 | d8b387359 |
15 | 7caba58a6 |
hex | 4aed91483 |
20113331331 has 4 divisors (see below), whose sum is σ = 26817775112. Its totient is φ = 13408887552.
The previous prime is 20113331327. The next prime is 20113331393. The reversal of 20113331331 is 13313331102.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20113331331 - 22 = 20113331327 is a prime.
It is a super-2 number, since 2×201133313312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20113331298 and 20113331307.
It is not an unprimeable number, because it can be changed into a prime (20113331311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3352221886 + ... + 3352221891.
It is an arithmetic number, because the mean of its divisors is an integer number (6704443778).
Almost surely, 220113331331 is an apocalyptic number.
20113331331 is a deficient number, since it is larger than the sum of its proper divisors (6704443781).
20113331331 is an equidigital number, since it uses as much as digits as its factorization.
20113331331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6704443780.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 20113331331 its reverse (13313331102), we get a palindrome (33426662433).
The spelling of 20113331331 in words is "twenty billion, one hundred thirteen million, three hundred thirty-one thousand, three hundred thirty-one".
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