Base | Representation |
---|---|
bin | 1011101101010010000… |
… | …1110000000011101011 |
3 | 201020011101022121001201 |
4 | 2323110201300003223 |
5 | 11243410313104003 |
6 | 232222202025031 |
7 | 20350201515625 |
oct | 2732441600353 |
9 | 636141277051 |
10 | 201134113003 |
11 | 78333a6607a |
12 | 32b934a8177 |
13 | 15c75284c65 |
14 | 9a4097dc15 |
15 | 5372ce7b1d |
hex | 2ed48700eb |
201134113003 has 2 divisors, whose sum is σ = 201134113004. Its totient is φ = 201134113002.
The previous prime is 201134112967. The next prime is 201134113027. The reversal of 201134113003 is 300311431102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201134113003 - 213 = 201134104811 is a prime.
It is not a weakly prime, because it can be changed into another prime (201134173003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100567056501 + 100567056502.
It is an arithmetic number, because the mean of its divisors is an integer number (100567056502).
Almost surely, 2201134113003 is an apocalyptic number.
201134113003 is a deficient number, since it is larger than the sum of its proper divisors (1).
201134113003 is an equidigital number, since it uses as much as digits as its factorization.
201134113003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 201134113003 its reverse (300311431102), we get a palindrome (501445544105).
The spelling of 201134113003 in words is "two hundred one billion, one hundred thirty-four million, one hundred thirteen thousand, three".
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