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2012002012243 is a prime number
BaseRepresentation
bin11101010001110100101…
…010100100110001010011
321010100022212202020121001
4131101310222210301103
5230431040003342433
64140145001442431
7265235166632266
oct35216452446123
97110285666531
102012002012243
11706315757273
12285b334a0417
13117966c51a72
146d54a872cdd
153750b9e957d
hex1d474aa4c53

2012002012243 has 2 divisors, whose sum is σ = 2012002012244. Its totient is φ = 2012002012242.

The previous prime is 2012002012219. The next prime is 2012002012261. The reversal of 2012002012243 is 3422102002102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2012002012243 - 217 = 2012001881171 is a prime.

It is a super-2 number, since 2×20120020122432 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2012002012243.

It is not a weakly prime, because it can be changed into another prime (2012002012283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006001006121 + 1006001006122.

It is an arithmetic number, because the mean of its divisors is an integer number (1006001006122).

Almost surely, 22012002012243 is an apocalyptic number.

2012002012243 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012002012243 is an equidigital number, since it uses as much as digits as its factorization.

2012002012243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 2012002012243 its reverse (3422102002102), we get a palindrome (5434104014345).

The spelling of 2012002012243 in words is "two trillion, twelve billion, two million, twelve thousand, two hundred forty-three".