Base | Representation |
---|---|
bin | 11101010001110100101… |
… | …010100100110001010011 |
3 | 21010100022212202020121001 |
4 | 131101310222210301103 |
5 | 230431040003342433 |
6 | 4140145001442431 |
7 | 265235166632266 |
oct | 35216452446123 |
9 | 7110285666531 |
10 | 2012002012243 |
11 | 706315757273 |
12 | 285b334a0417 |
13 | 117966c51a72 |
14 | 6d54a872cdd |
15 | 3750b9e957d |
hex | 1d474aa4c53 |
2012002012243 has 2 divisors, whose sum is σ = 2012002012244. Its totient is φ = 2012002012242.
The previous prime is 2012002012219. The next prime is 2012002012261. The reversal of 2012002012243 is 3422102002102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012002012243 - 217 = 2012001881171 is a prime.
It is a super-2 number, since 2×20120020122432 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2012002012243.
It is not a weakly prime, because it can be changed into another prime (2012002012283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006001006121 + 1006001006122.
It is an arithmetic number, because the mean of its divisors is an integer number (1006001006122).
Almost surely, 22012002012243 is an apocalyptic number.
2012002012243 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012002012243 is an equidigital number, since it uses as much as digits as its factorization.
2012002012243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 2012002012243 its reverse (3422102002102), we get a palindrome (5434104014345).
The spelling of 2012002012243 in words is "two trillion, twelve billion, two million, twelve thousand, two hundred forty-three".
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