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2012003304131 = 2137794120003
BaseRepresentation
bin11101010001110100101…
…111100000001011000011
321010100022222011212201202
4131101310233200023003
5230431040321213011
64140145045251415
7265235213622602
oct35216457401303
97110288155652
102012003304131
11706316459947
12285b33a03b6b
131179672b4ab2
146d54aacba39
153750bba223b
hex1d474be02c3

2012003304131 has 4 divisors (see below), whose sum is σ = 2012097445512. Its totient is φ = 2011909162752.

The previous prime is 2012003304019. The next prime is 2012003304187. The reversal of 2012003304131 is 1314033002102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2012003304131 - 230 = 2010929562307 is a prime.

It is a super-2 number, since 2×20120033041312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012003304631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47038625 + ... + 47081378.

It is an arithmetic number, because the mean of its divisors is an integer number (503024361378).

Almost surely, 22012003304131 is an apocalyptic number.

2012003304131 is a deficient number, since it is larger than the sum of its proper divisors (94141381).

2012003304131 is an equidigital number, since it uses as much as digits as its factorization.

2012003304131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94141380.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2012003304131 its reverse (1314033002102), we get a palindrome (3326036306233).

The spelling of 2012003304131 in words is "two trillion, twelve billion, three million, three hundred four thousand, one hundred thirty-one".

Divisors: 1 21377 94120003 2012003304131