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2012012020121 is a prime number
BaseRepresentation
bin11101010001110101010…
…000110000000110011001
321010100100120120200211012
4131101311100300012121
5230431100034120441
64140150000143305
7265235350663625
oct35216520600631
97110316520735
102012012020121
11706320372344
12285b36907b35
1311796904709c
146d54bd1a185
153750c8249eb
hex1d475430199

2012012020121 has 2 divisors, whose sum is σ = 2012012020122. Its totient is φ = 2012012020120.

The previous prime is 2012012020111. The next prime is 2012012020133. The reversal of 2012012020121 is 1210202102102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1913142650896 + 98869369225 = 1383164^2 + 314435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012012020121 is a prime.

It is a super-2 number, since 2×20120120201212 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2012012020096 and 2012012020105.

It is not a weakly prime, because it can be changed into another prime (2012012020111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006006010060 + 1006006010061.

It is an arithmetic number, because the mean of its divisors is an integer number (1006006010061).

Almost surely, 22012012020121 is an apocalyptic number.

It is an amenable number.

2012012020121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012012020121 is an equidigital number, since it uses as much as digits as its factorization.

2012012020121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 2012012020121 its reverse (1210202102102), we get a palindrome (3222214122223).

The spelling of 2012012020121 in words is "two trillion, twelve billion, twelve million, twenty thousand, one hundred twenty-one".