Base | Representation |
---|---|
bin | 11101010001110110100… |
… | …001101101011111101001 |
3 | 21010100102001111221021221 |
4 | 131101312201231133221 |
5 | 230431121002234423 |
6 | 4140152035102041 |
7 | 265236026245345 |
oct | 35216641553751 |
9 | 7110361457257 |
10 | 2012033243113 |
11 | 706331348503 |
12 | 285b41a41921 |
13 | 11797056807a |
14 | 6d550a82625 |
15 | 3750e617e5d |
hex | 1d47686d7e9 |
2012033243113 has 4 divisors (see below), whose sum is σ = 2012783165008. Its totient is φ = 2011283321220.
The previous prime is 2012033243081. The next prime is 2012033243167. The reversal of 2012033243113 is 3113423302102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2012033243113 - 25 = 2012033243081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2012033243183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 374956923 + ... + 374962288.
It is an arithmetic number, because the mean of its divisors is an integer number (503195791252).
Almost surely, 22012033243113 is an apocalyptic number.
It is an amenable number.
2012033243113 is a deficient number, since it is larger than the sum of its proper divisors (749921895).
2012033243113 is an equidigital number, since it uses as much as digits as its factorization.
2012033243113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 749921894.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2012033243113 its reverse (3113423302102), we get a palindrome (5125456545215).
The spelling of 2012033243113 in words is "two trillion, twelve billion, thirty-three million, two hundred forty-three thousand, one hundred thirteen".
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