Base | Representation |
---|---|
bin | 1001001001100101001100… |
… | …01000101100101000011011 |
3 | 2122020111022020212012102011 |
4 | 10210302212020230220123 |
5 | 10114123102003043113 |
6 | 110443105102250351 |
7 | 4144436422053502 |
oct | 444624610545033 |
9 | 78214266765364 |
10 | 20120414112283 |
11 | 6458024256911 |
12 | 230b579b869b7 |
13 | b2c468210c54 |
14 | 4d7b9459d839 |
15 | 24d5a138b63d |
hex | 124ca622ca1b |
20120414112283 has 2 divisors, whose sum is σ = 20120414112284. Its totient is φ = 20120414112282.
The previous prime is 20120414112251. The next prime is 20120414112341. The reversal of 20120414112283 is 38221141402102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20120414112283 - 25 = 20120414112251 is a prime.
It is not a weakly prime, because it can be changed into another prime (20120414112203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060207056141 + 10060207056142.
It is an arithmetic number, because the mean of its divisors is an integer number (10060207056142).
Almost surely, 220120414112283 is an apocalyptic number.
20120414112283 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120414112283 is an equidigital number, since it uses as much as digits as its factorization.
20120414112283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 20120414112283 its reverse (38221141402102), we get a palindrome (58341555514385).
The spelling of 20120414112283 in words is "twenty trillion, one hundred twenty billion, four hundred fourteen million, one hundred twelve thousand, two hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •