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2012102022011 = 5011140152901
BaseRepresentation
bin11101010001111010101…
…000000101001101111011
321010100120211221021012112
4131101322220011031323
5230431241104201021
64140202533202535
7265240522665044
oct35217250051573
97110524837175
102012102022011
11706367155074
12285b60a9044b
13117981899b43
146d559c678cb
15375156a1d5b
hex1d47aa0537b

2012102022011 has 4 divisors (see below), whose sum is σ = 2012142225024. Its totient is φ = 2012061819000.

The previous prime is 2012102021987. The next prime is 2012102022013. The reversal of 2012102022011 is 1102202012102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2012102022011 - 230 = 2011028280187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012102022013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20026340 + ... + 20126561.

It is an arithmetic number, because the mean of its divisors is an integer number (503035556256).

Almost surely, 22012102022011 is an apocalyptic number.

2012102022011 is a deficient number, since it is larger than the sum of its proper divisors (40203013).

2012102022011 is an equidigital number, since it uses as much as digits as its factorization.

2012102022011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40203012.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 2012102022011 its reverse (1102202012102), we get a palindrome (3114304034113).

Subtracting from 2012102022011 its reverse (1102202012102), we obtain a palindrome (909900009909).

The spelling of 2012102022011 in words is "two trillion, twelve billion, one hundred two million, twenty-two thousand, eleven".

Divisors: 1 50111 40152901 2012102022011