Base | Representation |
---|---|
bin | 101101110000000000010110… |
… | …010011001110010010010011 |
3 | 222101102120202200120202002112 |
4 | 231300000112103032102103 |
5 | 202333120113004133021 |
6 | 1551535020325335535 |
7 | 60245005126541543 |
oct | 5560002623162223 |
9 | 871376680522075 |
10 | 201211002021011 |
11 | 5912611a098694 |
12 | 1a6980595675ab |
13 | 883716802b098 |
14 | 37989433c7323 |
15 | 183de5eab7d5b |
hex | b700164ce493 |
201211002021011 has 2 divisors, whose sum is σ = 201211002021012. Its totient is φ = 201211002021010.
The previous prime is 201211002020999. The next prime is 201211002021047. The reversal of 201211002021011 is 110120200112102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201211002021011 - 210 = 201211002019987 is a prime.
It is not a weakly prime, because it can be changed into another prime (201211002011011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605501010505 + 100605501010506.
It is an arithmetic number, because the mean of its divisors is an integer number (100605501010506).
Almost surely, 2201211002021011 is an apocalyptic number.
201211002021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
201211002021011 is an equidigital number, since it uses as much as digits as its factorization.
201211002021011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 201211002021011 its reverse (110120200112102), we get a palindrome (311331202133113).
The spelling of 201211002021011 in words is "two hundred one trillion, two hundred eleven billion, two million, twenty-one thousand, eleven".
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