Base | Representation |
---|---|
bin | 101101110000000000010110… |
… | …110101011110011110000001 |
3 | 222101102120210022110221012211 |
4 | 231300000112311132132001 |
5 | 202333120122304001233 |
6 | 1551535021250022121 |
7 | 60245005266060115 |
oct | 5560002665363601 |
9 | 871376708427184 |
10 | 201211011000193 |
11 | 591261241708a7 |
12 | 1a698060577941 |
13 | 8837169b530cc |
14 | 3798944683745 |
15 | 183de6078d5cd |
hex | b70016d5e781 |
201211011000193 has 2 divisors, whose sum is σ = 201211011000194. Its totient is φ = 201211011000192.
The previous prime is 201211011000187. The next prime is 201211011000229. The reversal of 201211011000193 is 391000110112102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126218753722944 + 74992257277249 = 11234712^2 + 8659807^2 .
It is a cyclic number.
It is not a de Polignac number, because 201211011000193 - 233 = 201202421065601 is a prime.
It is not a weakly prime, because it can be changed into another prime (201211011000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605505500096 + 100605505500097.
It is an arithmetic number, because the mean of its divisors is an integer number (100605505500097).
Almost surely, 2201211011000193 is an apocalyptic number.
It is an amenable number.
201211011000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
201211011000193 is an equidigital number, since it uses as much as digits as its factorization.
201211011000193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 22.
Adding to 201211011000193 its reverse (391000110112102), we get a palindrome (592211121112295).
The spelling of 201211011000193 in words is "two hundred one trillion, two hundred eleven billion, eleven million, one hundred ninety-three", and thus it is an aban number.
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