Base | Representation |
---|---|
bin | 101101110000000001010001… |
… | …110010010000001110100011 |
3 | 222101102200100020110220020001 |
4 | 231300001101302100032203 |
5 | 202333124134000324141 |
6 | 1551535303340000431 |
7 | 60245041635402052 |
oct | 5560012162201643 |
9 | 871380306426201 |
10 | 201212000011171 |
11 | 59126591469446 |
12 | 1a698297830117 |
13 | 8837296a134c6 |
14 | 37989d9b70399 |
15 | 183debc4eda31 |
hex | b70051c903a3 |
201212000011171 has 2 divisors, whose sum is σ = 201212000011172. Its totient is φ = 201212000011170.
The previous prime is 201212000011151. The next prime is 201212000011303. The reversal of 201212000011171 is 171110000212102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201212000011171 - 223 = 201211991622563 is a prime.
It is not a weakly prime, because it can be changed into another prime (201212000011151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100606000005585 + 100606000005586.
It is an arithmetic number, because the mean of its divisors is an integer number (100606000005586).
Almost surely, 2201212000011171 is an apocalyptic number.
201212000011171 is a deficient number, since it is larger than the sum of its proper divisors (1).
201212000011171 is an equidigital number, since it uses as much as digits as its factorization.
201212000011171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 201212000011171 its reverse (171110000212102), we get a palindrome (372322000223273).
The spelling of 201212000011171 in words is "two hundred one trillion, two hundred twelve billion, eleven thousand, one hundred seventy-one".
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