Base | Representation |
---|---|
bin | 11101010001111011101… |
… | …100101100110100001001 |
3 | 21010100122002210011002002 |
4 | 131101323230230310021 |
5 | 230431310210304433 |
6 | 4140204414520345 |
7 | 265241131614122 |
oct | 35217354546411 |
9 | 7110562704062 |
10 | 2012120009993 |
11 | 706376320775 |
12 | 285b66b060b5 |
13 | 117985527512 |
14 | 6d55c3cb049 |
15 | 375170569e8 |
hex | 1d47bb2cd09 |
2012120009993 has 2 divisors, whose sum is σ = 2012120009994. Its totient is φ = 2012120009992.
The previous prime is 2012120009987. The next prime is 2012120010079. The reversal of 2012120009993 is 3999000212102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1870023430144 + 142096579849 = 1367488^2 + 376957^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012120009993 - 230 = 2011046268169 is a prime.
It is a super-2 number, since 2×20121200099932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2012120009693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006060004996 + 1006060004997.
It is an arithmetic number, because the mean of its divisors is an integer number (1006060004997).
Almost surely, 22012120009993 is an apocalyptic number.
It is an amenable number.
2012120009993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012120009993 is an equidigital number, since it uses as much as digits as its factorization.
2012120009993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 38.
The spelling of 2012120009993 in words is "two trillion, twelve billion, one hundred twenty million, nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •