Base | Representation |
---|---|
bin | 1001001001100110101010… |
… | …00111000110001110110011 |
3 | 2122020120100011211022201001 |
4 | 10210303111013012032303 |
5 | 10114131210232101003 |
6 | 110443315214222431 |
7 | 4144465101635461 |
oct | 444632507061663 |
9 | 78216304738631 |
10 | 20121202222003 |
11 | 6458399106363 |
12 | 230b759ab4a17 |
13 | b2c56258ca6c |
14 | 4d7c2b111831 |
15 | 24d5ea66561d |
hex | 124cd51c63b3 |
20121202222003 has 2 divisors, whose sum is σ = 20121202222004. Its totient is φ = 20121202222002.
The previous prime is 20121202221983. The next prime is 20121202222039. The reversal of 20121202222003 is 30022220212102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121202222003 - 213 = 20121202213811 is a prime.
It is a super-4 number, since 4×201212022220034 (a number of 54 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (20121202222063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060601111001 + 10060601111002.
It is an arithmetic number, because the mean of its divisors is an integer number (10060601111002).
Almost surely, 220121202222003 is an apocalyptic number.
20121202222003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121202222003 is an equidigital number, since it uses as much as digits as its factorization.
20121202222003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 20121202222003 its reverse (30022220212102), we get a palindrome (50143422434105).
The spelling of 20121202222003 in words is "twenty trillion, one hundred twenty-one billion, two hundred two million, two hundred twenty-two thousand, three".
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