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201212121121153 is a prime number
BaseRepresentation
bin101101110000000001011001…
…000000010000000110000001
3222101102200122200100220212221
4231300001121000100012001
5202333124411001334103
61551535323343451041
760245044635665302
oct5560013100200601
9871380580326787
10201212121121153
115912664386913a
121a6983102b6a81
1388372b5b3870c
143798a0bc987a9
15183dec7e731bd
hexb70059010181

201212121121153 has 2 divisors, whose sum is σ = 201212121121154. Its totient is φ = 201212121121152.

The previous prime is 201212121121139. The next prime is 201212121121169. The reversal of 201212121121153 is 351121121212102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 200506534561089 + 705586560064 = 14160033^2 + 839992^2 .

It is a cyclic number.

It is not a de Polignac number, because 201212121121153 - 217 = 201212120990081 is a prime.

It is a super-4 number, since 4×2012121211211534 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (201212121122153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100606060560576 + 100606060560577.

It is an arithmetic number, because the mean of its divisors is an integer number (100606060560577).

Almost surely, 2201212121121153 is an apocalyptic number.

It is an amenable number.

201212121121153 is a deficient number, since it is larger than the sum of its proper divisors (1).

201212121121153 is an equidigital number, since it uses as much as digits as its factorization.

201212121121153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 25.

Adding to 201212121121153 its reverse (351121121212102), we get a palindrome (552333242333255).

The spelling of 201212121121153 in words is "two hundred one trillion, two hundred twelve billion, one hundred twenty-one million, one hundred twenty-one thousand, one hundred fifty-three".