Base | Representation |
---|---|
bin | 101101110000000001011001… |
… | …100111001100101111011001 |
3 | 222101102200200101120122012122 |
4 | 231300001121213030233121 |
5 | 202333124421110043113 |
6 | 1551535324350351025 |
7 | 60245045121530564 |
oct | 5560013147145731 |
9 | 871380611518178 |
10 | 201212131331033 |
11 | 59126649601a59 |
12 | 1a6983137bb475 |
13 | 88372b7ca1974 |
14 | 3798a0d3954db |
15 | 183dec8cdd408 |
hex | b700599ccbd9 |
201212131331033 has 4 divisors (see below), whose sum is σ = 201212303907300. Its totient is φ = 201211958754768.
The previous prime is 201212131331021. The next prime is 201212131331041. The reversal of 201212131331033 is 330133131212102.
201212131331033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 140896591380169 + 60315539950864 = 11869987^2 + 7766308^2 .
It is a cyclic number.
It is not a de Polignac number, because 201212131331033 - 210 = 201212131330009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201212131330993 and 201212131331011.
It is not an unprimeable number, because it can be changed into a prime (201212131331053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84527258 + ... + 86875091.
It is an arithmetic number, because the mean of its divisors is an integer number (50303075976825).
Almost surely, 2201212131331033 is an apocalyptic number.
It is an amenable number.
201212131331033 is a deficient number, since it is larger than the sum of its proper divisors (172576267).
201212131331033 is a wasteful number, since it uses less digits than its factorization.
201212131331033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172576266.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 201212131331033 its reverse (330133131212102), we get a palindrome (531345262543135).
The spelling of 201212131331033 in words is "two hundred one trillion, two hundred twelve billion, one hundred thirty-one million, three hundred thirty-one thousand, thirty-three".
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